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Moribaskasey
Moribaskasey Moribaskasey
  • 22-05-2016
  • Mathematics
Answered

Given a mean of 9 and a standard deviation of 2.8, what is the z-score of the value 11 rounded to the nearest tenth?



–0.9


–0.7


0.9


0.7

Verified Answer :

Anonymous Anonymous
  • 03-06-2016

The answer is 0.7. Since the formula of the z-score is the difference of the score (x) and the mean divided by the standard deviation (SD)...
 
z= [ (x-mean)/SD ] 

You simply substitute the values given.

z = (11-9)/2.8
z=2/2.8
z=0.714

Then round it to the nearest tenth...

z- = 0.7

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