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kat145234 kat145234
  • 24-02-2014
  • Mathematics
Answered

using special products what is (wx-y)^2

Verified Answer :

priyambaksi
priyambaksi priyambaksi
  • 24-02-2014

i think that supposed to be (wx - y^2)^2?

If so, multiply using FOIL:


First: wx wx = w^2x^2


Outside: wx -y^2 = -wxy^2


Inside: -y wx = -wxy^2


Last: -y^2 -y^2 = y^4


Combine w^2x^2 - 2wxy^2 + y^4

Answer Link
isaacrosado04
isaacrosado04 isaacrosado04
  • 29-10-2020

Answer:

I believe it is wx^2 - 2ywx + y^2

Step-by-step explanation:

seperated into (wx-y)(wx-y) and used FOIL

Answer Link

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