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Pilesacolaechemog
Pilesacolaechemog Pilesacolaechemog
  • 16-05-2016
  • Mathematics
Answered

Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 π ).

a.π and π/3

b.π, π/3, and 5π/3

c.1 and 2π/3

d.1, 2π/3, and 4π/3

e.1, π/3, and 5π/3

Verified Answer :

nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 27-05-2016

Let cos x = a, then
2a^2 + a - 1 = 0,
solving the quadratic equation, we have:
a = 0.5 or -1.

i.e. cos x = 0.5 or cos x = -1
for cos x = 0.5,
x = pi/3, 2pi - pi/3 = pi/3, 5pi/3

for cos x = -1,
x = pi

therefore, x = pi, pi/3, 5pi/3
Answer: B

Answer Link
sofia50923
sofia50923 sofia50923
  • 26-01-2022

Answer:

Option B is correct for plato

Step-by-step explanation:

\(\pi ,\frac{\pi }{3}, and \frac{5\pi }{3}\)

Answer Link

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