(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
\(\sqrt[3]{(3x+4)^3}\) = \(\sqrt[3]{2197}\)
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3
\(\frac{3x}{3} = \frac{9}{3}\)
3 and 3 cancels out
x = 3
