\(\frac{4}{44} =\frac{1\times4}{11\times 4}= \frac{1}{11} = \frac{1\times 7}{11\times 7} = \frac{7}{77}\\\
= 7\)
Your answer is B.
Another way to solve it is by cross multiplying.
\(\frac{4}{44} = \frac{n}{77}\\\\4 \times 77 = 44n\\\
= \frac{4\times 77}{44}\\\
= 7\)
Answer is B.
