mulakalav mulakalav

16-04-2016
Mathematics

Answered

Two cities are 210 km apart. A train traveled this distance in 4 2/3 hours and then made the return trip at a speed of 50 2/5 km/h. How many times greater (or less) was the train’s speed on the return trip?

Verified Answer :

Anonymous Anonymous

16-04-2016

\(4 \frac{2}{3}= \frac{14}{3}\)

So, \(\frac{210km}{ \frac{14}{3}hr }= 45km/h\)

\(50 \frac{2}{5} = \frac{252}{5}\)

So, \(\frac{252}{5}/45= 1.12\) times greater on the return trip.

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