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Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?

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Willchemistry

Stoichiometry of the reaction:

2 KClO₃    =    2 KCl  +   3 O₂
  ↓                                      ↓
    
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!

linhle9140

Answer:

the answer is 3

Explanation:

2 mol of potassium chlorate x \(\frac{3}{2}\) = 3

also just did it on edge

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