\(1l=1dm^{3}=10cm*10cm*10cm=1000cm^{3}\)
This means that the volume of block is :
\(V=4,77*1000cm^{3}=4770cm^{3}\)
\(1kg=1000g\)
This means that the mass of block is:
\(M=12,88*1000g=12880g\)
The density of the aluminum can be counted with equation:
\(ς=\frac{M}{V}=\frac{12880}{4770}=2,7\frac{g}{cm^{3}}\)