use quadratic formula if you had ax^2+bx+c=0, then x=\(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\) a=1 b=? c=34 subsitute \(\frac{-b+/- \sqrt{b^{2}-4(1)(34)} }{2(1)}\)=5+/-3i \(\frac{-b+/- \sqrt{b^{2}-136} }{2}\)=5+/-3i make 5+/-3 into fraction over 2,(10+/-6i)/2 \(\frac{-b+/- \sqrt{b^{2}-136} }{2}\)=(10+/-6i)/2 multiply both sides by 2 \(-b+/- \sqrt{b^{2}-136}\)=10+/-6i we conclude that -b=10 b=-10
