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marty2752
marty2752 marty2752
  • 07-09-2014
  • Mathematics
Answered

How to solve 6x^2+5x-4=0

Verified Answer :

Anonymous Anonymous
  • 07-09-2014

\(6x^2+5x-4=0\\\\6x^2+8x-3x-4\\\\2x(3x+4)-1(3x+4)=0\\\\(3x+4)(2x-1)=0\iff3x+4=0\ or\ 2x-1=0\\\\3x=-4\ or\ 2x=1\\\\\boxed{x=-\frac{4}{3}\ or\ x=\frac{1}{2}}\)

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