How do i write (n+5)(2n-3) in general form?
(n - 5)(2n - 3)n(2n - 3) - 5(2n - 3)n(2n) - n(3) - 5(2n) + 5(3)2n² - 3n - 10n + 152n² - 13n + 15a₂ = 2a₁ = -13a₀ = 15
\((n+5)(2n-3) \\ \\ 2n^2 - 3n + 10n - 15 \\ \\ 2n^2 + (-3n + 10n) - 15 \\ \\ 2n^2 + 7n - 15 \\ \\\)The final result is: 2n² + 7n - 15.
